Two wires each of radius of cross section r b | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The current $I$ flowing through a conductor is given by the formula $I = n e A V_{d}$,where $n$ is the charge carrier density,$e$ is the elementar

Vedclass · Accepted Answer

$4 : 1$

Vedclass · Answer

(C) The current $I$ flowing through a conductor is given by the formula $I = n e A V_{d}$,where $n$ is the charge carrier density,$e$ is the elementary charge,$A$ is the cross-sectional area,and $V_{d}$ is the drift velocity.Since the wires are connected in series,the current $I$ flowing through both wires must be the same.Given that both wires have the same radius $r$,their cross-sectional areas $A$ are also equal.Therefore,$n_{1} e A V_{d_{1}} = n_{2} e A V_{d_{2}}$.This simplifies to $n_{1} V_{d_{1}} = n_{2} V_{d_{2}}$,which implies $\frac{V_{d_{1}}}{V_{d_{2}}} = \frac{n_{2}}{n_{1}}$.Given the ratio of charge carrier densities is $\frac{n_{1}}{n_{2}} = \frac{1}{4}$,we have $\frac{n_{2}}{n_{1}} = \frac{4}{1}$.Thus,the ratio of drift velocities is $\frac{V_{d_{1}}}{V_{d_{2}}} = 4 : 1$.

Two wires each of radius of cross section $r$ but of different materials are connected together end to end (in series). If the densities of charge carriers in the two wires are in the ratio $1 : 4$,the drift velocity of electrons in the two wires will be in the ratio:

Similar Questions

An electric cell of emf $E$ is connected across a copper wire of diameter $d$ and length $l$. The drift velocity of electrons in the wire is $v_{d}$. If the length of the wire is changed to $2l$, the new drift velocity of electrons in the copper wire will be

Derive the relation between electric current and drift velocity.

The dominant force experienced by an electron moving in a wire is

$A$ current of $1.6\, A$ is flowing through a wire having a cross-sectional area of $1\, mm^2$. If the density of free electrons in the material of the wire is $10^{29}\, m^{-3}$,the drift velocity of the electrons will be:

Mobility of free electrons in a conductor is

Vedclass Test Series

Exam Paper Generator

Online Exam Module