Under a constant pressure head,the rate of flow of liquid through a capillary tube is $V$. If the length of the capillary is doubled and the diameter of the bore is halved,the rate of flow would become

  • A
    $V / 4$
  • B
    $16 V$
  • C
    $V / 8$
  • D
    $V / 32$

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Similar Questions

The rate of steady volume flow of water through a capillary tube of length $l$ and radius $r$,under a pressure difference of $p$ is $V$. This tube is connected with another tube of the same length but half the radius,in series. Then,the rate of steady volume flow through them is (The pressure difference across the combination is $p$.)

Range of Reynolds number are given in Column - $I$ and types of flow are given in Column - $II$. Match them appropriately.
Column - $I$ Column - $II$
$(a)$ $R_e > 2000$ $(i)$ Streamline
$(b)$ $1000 < R_e < 2000$ $(ii)$ Turbulent
$(iii)$ Unsteady

Water from a pipe is coming at a rate of $100\, L/min$. If the radius of the pipe is $5\, cm$, the Reynolds number for the flow is of the order of: (density of water $= 1000\, kg/m^3$, coefficient of viscosity of water $= 1\, mPa\, s$)

In Poiseuille's method for the determination of the coefficient of viscosity,the physical quantity that requires the greatest accuracy in measurement is:

Which of the following quantities has the dimensions of $\frac{\pi P r^4}{8 Q l}$? (Where $P =$ pressure,$r =$ radius,$Q =$ volume flow rate in $m^3/s$,and $l =$ length.)

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