Vector A is pointing eastwards and vector B i | vedclass

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(A) Let the unit vectors be $\hat{i}$ (East) and $\hat{j}$ (North). So,$A = A\hat{i}$ and $B = B\hat{j}$.$(A) (A+B) = A\hat{i} + B\hat{j}$,which point

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$(A \rightarrow p, B \rightarrow s, C \rightarrow q, D \rightarrow s)$

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(A) Let the unit vectors be $\hat{i}$ (East) and $\hat{j}$ (North). So,$A = A\hat{i}$ and $B = B\hat{j}$.$(A) (A+B) = A\hat{i} + B\hat{j}$,which points in the North-east direction. Thus,$(A) ightarrow (p)$.$(B) (A-B) = A\hat{i} - B\hat{j}$,which points in the South-east direction. This is not listed in Column $II$,so $(B) ightarrow (s)$.$(C) (A 	imes B) = (A\hat{i}) 	imes (B\hat{j}) = AB(\hat{i} 	imes \hat{j}) = AB\hat{k}$,which points Vertically upwards. Thus,$(C) ightarrow (q)$.$(D) (A 	imes B) 	imes (A 	imes B) = 0$,because the cross product of any vector with itself is zero. This is not listed in Column $II$,so $(D) ightarrow (s)$.Therefore,the correct matching is $(A ightarrow p, B ightarrow s, C ightarrow q, D ightarrow s)$.

Column $I$	Column $II$
$(A) (A+B)$	$(p)$ North-east
$(B) (A-B)$	$(q)$ Vertically upwards
$(C) (A \times B)$	$(r)$ Vertically downwards
$(D) (A \times B) \times (A \times B)$	$(s)$ None

Vector $A$ is pointing eastwards and vector $B$ is pointing northwards. Match the following two columns:

Column $I$ Column $II$

$(A) (A+B)$ $(p)$ North-east

$(B) (A-B)$ $(q)$ Vertically upwards

$(C) (A \times B)$ $(r)$ Vertically downwards

$(D) (A \times B) \times (A \times B)$ $(s)$ None

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Vector $A$ is pointing eastwards and vector $B$ is pointing northwards. Match the following two columns: Column $I$ Column $II$ $(A) (A+B)$ $(p)$ North-east $(B) (A-B)$ $(q)$ Vertically upwards $(C) (A \times B)$ $(r)$ Vertically downwards $(D) (A \times B) \times (A \times B)$ $(s)$ None