The velocity of a body upon reaching the poin | vedclass

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(D) When a body is projected upwards with an initial velocity $u$,it undergoes constant deceleration due to gravity $(g)$.At the maximum height,its ve

Vedclass · Accepted Answer

$v = u$

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(D) When a body is projected upwards with an initial velocity $u$,it undergoes constant deceleration due to gravity $(g)$.At the maximum height,its velocity becomes $0$.As it falls back down to the point of projection,it undergoes constant acceleration due to gravity $(g)$ over the same displacement.Using the kinematic equation $v^2 = u^2 + 2as$,where $a = -g$ for the upward journey and $a = g$ for the downward journey,the final velocity $v$ at the starting point will have the same magnitude as the initial velocity $u$,but in the opposite direction.Therefore,the speed of the body upon returning to the point of projection is $v = u$.

The velocity of a body upon reaching the point from which it was projected upwards is:

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