Verify whether the given value of x is a solu | vedclass

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Question

(A) Given equation: $x + \frac{1}{x} = 3 \frac{1}{3}$.Convert the mixed fraction to an improper fraction: $3 \frac{1}{3} = \frac{3 	imes 3 + 1}{3} =

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(A) Given equation: $x + \frac{1}{x} = 3 \frac{1}{3}$.Convert the mixed fraction to an improper fraction: $3 \frac{1}{3} = \frac{3 	imes 3 + 1}{3} = \frac{10}{3}$.So,the equation is $x + \frac{1}{x} = \frac{10}{3}$.Substitute $x = \frac{1}{3}$ into the left-hand side $(LHS)$ of the equation:$LHS$ $= \frac{1}{3} + \frac{1}{1/3} = \frac{1}{3} + 3$.$LHS$ $= \frac{1 + 9}{3} = \frac{10}{3}$.Since $LHS$ $= \frac{10}{3}$ and $RHS$ $= \frac{10}{3}$,$LHS$ $=$ $RHS$.Therefore,$x = \frac{1}{3}$ is a solution of the given quadratic equation.

Verify whether the given value of $x$ is a solution of the quadratic equation or not: $x + \frac{1}{x} = 3 \frac{1}{3}$; $x = \frac{1}{3}$.

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