Verify whether $3$ and $5$ are zeros of the polynomial $x^{2}-x-6$ or not.

(N/A) Let $p(x) = x^{2}-x-6$.
For $x = 3$:
$p(3) = (3)^{2} - 3 - 6 = 9 - 3 - 6 = 0$.
Since $p(3) = 0$,$3$ is a zero of the polynomial $x^{2}-x-6$.
For $x = 5$:
$p(5) = (5)^{2} - 5 - 6 = 25 - 5 - 6 = 14$.
Since $p(5) \neq 0$,$5$ is not a zero of the polynomial $x^{2}-x-6$.