The vertices of a figure are $(-2, 2), (-2, -1), (3, -1),$ and $(3, 2)$. This figure is a:

The Cartesian coordinates of the point whose polar coordinates are $\left(\frac{1}{2}, 120^{\circ}\right)$ are:

$A$ square,of each side $2$,lies above the $x-$axis and has one vertex at the origin. If one of the sides passing through the origin makes an angle $30^o$ with the positive direction of the $x-$axis,then the sum of the $x-$coordinates of the vertices of the square is

If the polar coordinates of a point are $\left( \sqrt{2}, -\frac{3\pi}{4} \right)$,what are its Cartesian coordinates?

Two fixed points are $A(a, 0)$ and $B(-a, 0)$. If $\angle A - \angle B = \theta$,then the locus of point $C$ of triangle $ABC$ will be

The point of intersection of the diagonals of a square is at the origin,and the coordinate axes are drawn along the diagonals. If the side length of the square is $a$,then which of the following is $NOT$ a vertex of the square?