$A$ water drop whose radius is $0.0015 \, mm$ is falling through the air. If the coefficient of viscosity of air is $1.8 \times 10^{-5} \, kg/(m \cdot s)$,then assuming the buoyancy force is negligible,the terminal velocity of the drop will be:

  • A
    $2.72 \times 10^{-4} \, m/s$
  • B
    $2.72 \times 10^{-3} \, m/s$
  • C
    $2.72 \times 10^{-2} \, m/s$
  • D
    $2.72 \times 10^{-1} \, m/s$

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