Weight of a body is maximum at

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(B) The weight of a body is given by the formula $W = m 	imes g$,where $m$ is the mass of the body and $g$ is the acceleration due to gravity.Since t

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Poles of earth

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(B) The weight of a body is given by the formula $W = m 	imes g$,where $m$ is the mass of the body and $g$ is the acceleration due to gravity.Since the mass $m$ is constant,the weight $W$ is directly proportional to the acceleration due to gravity $g$.The value of $g$ on the surface of the Earth varies with latitude. It is given by $g = g_0 - \omega^2 R \cos^2 \phi$,where $\phi$ is the latitude.At the equator,$\phi = 0^\circ$,so $\cos^2 \phi$ is maximum,making $g$ minimum.At the poles,$\phi = 90^\circ$,so $\cos^2 \phi = 0$,making $g$ maximum.Therefore,the weight of a body is maximum at the poles of the Earth.Thus,the correct option is $B$.

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