What are X, Y, Z in the following reaction se | vedclass

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(A) Step $1$: Oxidation of $but-2-ene$ $(CH_3-CH=CH-CH_3)$ with acidic $KMnO_4$ $(X)$ gives ethanoic acid $(CH_3COOH)$. Step $2$: Ethanoic acid reacts

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$KMnO_4 / H^{+} ; SOCl_2 ;$ Acetophenone

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(A) Step $1$: Oxidation of $but-2-ene$ $(CH_3-CH=CH-CH_3)$ with acidic $KMnO_4$ $(X)$ gives ethanoic acid $(CH_3COOH)$. Step $2$: Ethanoic acid reacts with $SOCl_2$ $(Y)$ to form ethanoyl chloride $(CH_3COCl)$. Step $3$: Ethanoyl chloride reacts with benzene in the presence of anhydrous $AlCl_3$ (Friedel-Crafts acylation) to form acetophenone ($Z$,$C_6H_5COCH_3$). Therefore,$X = KMnO_4 / H^{+}$,$Y = SOCl_2$,and $Z = 	ext{Acetophenone}$.

What are $X, Y, Z$ in the following reaction sequence?
$CH_3-CH=CH-CH_3$ $\xrightarrow{X} CH_3COOH$ $\xrightarrow{Y} CH_3COCl$ $\xrightarrow[\text{Anhy. } AlCl_3]{\text{Benzene}} Z$

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What are $X, Y, Z$ in the following reaction sequence? $CH_3-CH=CH-CH_3$ $\xrightarrow{X} CH_3COOH$ $\xrightarrow{Y} CH_3COCl$ $\xrightarrow[\text{Anhy. } AlCl_3]{\text{Benzene}} Z$