What are the values of (x, y, z, t),if 3begin | vedclass

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(B) Given the matrix equation: $3\begin{bmatrix} x & y \ z & t \end{bmatrix} = \begin{bmatrix} x & 6 \ -1 & 2t \end{bmatrix} + \begin{bmatrix} 4 & x

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$(2, 4, 1, 3)$

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(B) Given the matrix equation: $3\begin{bmatrix} x & y \ z & t \end{bmatrix} = \begin{bmatrix} x & 6 \ -1 & 2t \end{bmatrix} + \begin{bmatrix} 4 & x+y \ z+t & 3 \end{bmatrix}$Multiplying the scalar $3$ into the first matrix,we get:$\begin{bmatrix} 3x & 3y \ 3z & 3t \end{bmatrix} = \begin{bmatrix} x+4 & 6+x+y \ -1+z+t & 2t+3 \end{bmatrix}$Since the two matrices are equal,their corresponding elements must be equal:$1) \ 3x = x + 4 \implies 2x = 4 \implies x = 2$$2) \ 3t = 2t + 3 \implies t = 3$$3) \ 3z = -1 + z + t \implies 2z = -1 + 3 \implies 2z = 2 \implies z = 1$$4) \ 3y = 6 + x + y \implies 2y = 6 + 2 \implies 2y = 8 \implies y = 4$Thus,the values are $(x, y, z, t) = (2, 4, 1, 3)$.

What are the values of $(x, y, z, t)$,if $3\begin{bmatrix} x & y \\ z & t \end{bmatrix} = \begin{bmatrix} x & 6 \\ -1 & 2t \end{bmatrix} + \begin{bmatrix} 4 & x+y \\ z+t & 3 \end{bmatrix}$?

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