What hybrid orbitals are present in the follo | vedclass

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(B) The hybridization of carbon atoms is determined by the number of sigma bonds and lone pairs attached to them.$1$. The terminal $CH_3$ groups are b

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$sp^2$ and $sp^3$

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(B) The hybridization of carbon atoms is determined by the number of sigma bonds and lone pairs attached to them.$1$. The terminal $CH_3$ groups are bonded to four atoms (three $H$ and one $C$),so they are $sp^3$ hybridized.$2$. The $CH_2$ group is bonded to four atoms (two $H$ and two $C$),so it is $sp^3$ hybridized.$3$. The $CH$ groups involved in the double bond are bonded to three atoms (one $H$ and two $C$),so they are $sp^2$ hybridized.Therefore,the compound contains $sp^2$ and $sp^3$ hybridized carbon atoms.Structure: $\mathop{CH_3}\limits_{sp^3} - \mathop{CH}\limits_{sp^2} = \mathop{CH}\limits_{sp^2} - \mathop{CH_2}\limits_{sp^3} - \mathop{CH_3}\limits_{sp^3}$

What hybrid orbitals are present in the following compound $H_3C - CH = CH - CH_2 - CH_3$?

Similar Questions

Which of the following compounds do not have $sp^3$ carbon atom$(s)$?
$I$. Acetone
$II$. Acetic acid
$III$. Buta-$1,3$-diene
$IV$. Propyne
$V$. Naphthalene

Which of the following does not contain an $sp^2$ hybridized carbon?

In the compound $^1CH_2 = ^2CH - ^3CH_2 - ^4CH_2 - ^5C \equiv ^6CH$, the $C_2 - C_3$ bond is of which type?

Amongst the given options,the compound$(s)$ in which all the atoms are in one plane in all the possible conformations (if any),is (are):
$(A)$ $CH_2=CH-CH=CH_2$
$(B)$ $HC\equiv C-CH=CH_2$
$(C)$ $H_2C=C=O$
$(D)$ $H_2C=C=CH_2$

How many $(i)$ $sp^{2}$ hybridised carbon atoms and $(ii)$ $\pi$ bonds are present in the following compound?

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