What is the {v_{rms}} of gas molecules in equ | vedclass

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(C) The root mean square speed $({v_{rms}})$ of gas molecules is given by the formula ${v_{rms} = \sqrt{\frac{3RT}{M}}}$,where $R$ is the universal ga

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Depends on the temperature of the gas

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(C) The root mean square speed $({v_{rms}})$ of gas molecules is given by the formula ${v_{rms} = \sqrt{\frac{3RT}{M}}}$,where $R$ is the universal gas constant,$T$ is the absolute temperature,and $M$ is the molar mass of the gas.Since the temperature $T$ of a gas in equilibrium is greater than $0 \ K$,the ${v_{rms}}$ value is always positive and non-zero.Therefore,the statement that ${v_{rms}}$ is zero is incorrect; it depends on the temperature and the molar mass of the gas.

What is the ${v_{rms}}$ of gas molecules in equilibrium?

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