What is the order of the speed of gas molecul | vedclass

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(B) The root mean square speed $(v_{rms})$ of gas molecules is given by the formula $v_{rms} = \sqrt{\frac{3RT}{M}}$.For air at room temperature $(T \

Vedclass · Accepted Answer

$10^2 \ m/s$

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(B) The root mean square speed $(v_{rms})$ of gas molecules is given by the formula $v_{rms} = \sqrt{\frac{3RT}{M}}$.For air at room temperature $(T \approx 300 \ K)$,the molar mass $(M)$ is approximately $29 	imes 10^{-3} \ kg/mol$.Substituting these values: $v_{rms} = \sqrt{\frac{3 	imes 8.314 	imes 300}{29 	imes 10^{-3}}} \approx 460 \ m/s$.This value is of the order of $10^2 \ m/s$ to $10^3 \ m/s$,but typically,for common gases like nitrogen or oxygen at standard conditions,it is approximately $500 \ m/s$,which falls under the order of $10^2 \ m/s$ (specifically closer to $10^2$ than $10^3$ in magnitude).Therefore,the correct order is $10^2 \ m/s$.

What is the order of the speed of gas molecules?

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