What is the percentage of H_2O in Fe(CNS)_3 c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The molar mass of $Fe(CNS)_3 \cdot 3H_2O$ is calculated as follows:$Fe = 56$,$C = 12$,$N = 14$,$S = 32$,$H = 1$,$O = 16$.$Molar \ mass = 56 + 3

Vedclass · Accepted Answer

$19$

Vedclass · Answer

(C) The molar mass of $Fe(CNS)_3 \cdot 3H_2O$ is calculated as follows:$Fe = 56$,$C = 12$,$N = 14$,$S = 32$,$H = 1$,$O = 16$.$Molar \ mass = 56 + 3 	imes (12 + 14 + 32) + 3 	imes (2 	imes 1 + 16) = 56 + 3 	imes 58 + 3 	imes 18 = 56 + 174 + 54 = 284 \ g/mol$.The mass of $3H_2O$ is $3 	imes 18 = 54 \ g/mol$.The percentage of $H_2O$ is calculated as:$\frac{Mass \ of \ 3H_2O}{Total \ molar \ mass} 	imes 100 = \frac{54}{284} 	imes 100 \approx 19.01\%$.Thus,the correct option is $C$.

What is the percentage of $H_2O$ in $Fe(CNS)_3 \cdot 3H_2O$?

Similar Questions

$0.765 \ g$ of an acid gives $0.535 \ g$ of $CO_2$ and $0.13 \ g$ of $H_2O$. The ratio of the percentage of $C$ and $H$ is:

$A$ metal $M$ sulfate contains $9.87 \% \, M$. If it is isomorphous with $ZnSO_4 \cdot 7H_2O$,what is the atomic mass of $M$ (in $.3$)?

The empirical formula of a hydrocarbon containing $80\%$ carbon and $20\%$ hydrogen is:

$A$ compound contains $4.07\%$ hydrogen,$24.27\%$ carbon,and $71.65\%$ chlorine. Its molar mass is $98.96\ g/mol$. What are its empirical and molecular formulas?

$0.24 \ g$ of an organic compound gave $0.22 \ g$ $CO_2$ on complete combustion. If it contains $1.66 \%$ hydrogen,then the percentage of $C$ and $O$ will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module