What is the IUPAC name of the compound? | vedclass

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(A) $1$. The principal functional group is the ketone,which gets the lowest possible locant. Thus,the carbonyl carbon is assigned position $1$.$2$. Nu

Vedclass · Accepted Answer

$2-$chloro$-4-$methylcyclohexanone

Vedclass · Answer

(A) $1$. The principal functional group is the ketone,which gets the lowest possible locant. Thus,the carbonyl carbon is assigned position $1$.$2$. Numbering the ring to give the substituents the lowest possible locants,we move towards the chlorine atom to give it position $2$.$3$. The methyl group is then at position $4$.$4$. Combining these,the $IUPAC$ name is $2-$chloro$-4-$methylcyclohexanone.

What is the $IUPAC$ name of the compound?

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