What is the coordination number of the central metal ion if it forms an octahedral complex?

Which type of atomic orbitals hybridize to form a square planar complex?

Which one of the following ions is not tetrahedral in shape?

Match the hybridisation in Column $I$ with the complexes in Column $II$. The options represent the matches for $(A), (B), (C), (D)$ respectively.

Column $I$	Column $II$
$(A)$ $sp^3$	$(i)$ $[Co(NH_3)_6]^{3+}$
$(B)$ $dsp^2$	$(ii)$ $[Ni(CO)_4]$
$(C)$ $sp^3d^2$	$(iii)$ $[Pt(NH_3)_2Cl_2]$
$(D)$ $d^2sp^3$	$(iv)$ $[CoF_6]^{3-}$
	$(v)$ $[Fe(CO)_5]$

Match List – $I$ with List – $II$:

List - $I$ (Complex)	List – $II$ (Geometry)
$(a)$ $[Co(NH_3)_6]^{3+}$	$(i)$ Trigonal bipyramidal
$(b)$ $[NiCl_4]^{2-}$	(ii) Octahedral
$(c)$ $[Ni(CN)_4]^{2-}$	(iii) Tetrahedral
$(d)$ $[Fe(CO)_5]$	(iv) Square planar

Choose the correct answer from the options given below.

The ammine complexes of metal ions $Cu^{2+}$,$Ni^{2+}$ and $Zn^{2+}$ have shapes respectively: