What is the correct order of atomic radius of | vedclass

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Question

(B) The atomic radius decreases across a period from left to right due to an increase in effective nuclear charge. Across $Period-2$,the order is $B <

Vedclass · Accepted Answer

$B < Be < Al < Na$

Vedclass · Answer

(B) The atomic radius decreases across a period from left to right due to an increase in effective nuclear charge. Across $Period-2$,the order is $B Across $Period-3$,the order is $Al Down a group,the atomic radius increases due to the addition of a new shell. Comparing the elements: $B$ (Period $2$,Group $13$) has the smallest radius. $Be$ (Period $2$,Group $2$) is larger than $B$. $Al$ (Period $3$,Group $13$) is larger than $B$ and $Be$. $Na$ (Period $3$,Group $1$) is the largest among these. Therefore,the correct order of atomic radius is $B < Be < Al < Na$.

What is the correct order of atomic radius of $Al, Na, B$ and $Be$?

Similar Questions

From the given set of species,point out the species from each set having the least atomic/ionic radius:
$(A)$ $F^{-}, Na^{+}, Mg^{+2}$
$(B)$ $Ni, Cu, Zn$
$(C)$ $N^{-3}, Cs^{+}, H^{-}$
$(D)$ $Li, Li^{+}, Be^{+2}$

Which of the following sequences is the correct order of the size of species?

Consider the isoelectronic species,$Na^{+}$,$Mg^{2+}$,$F^{-}$,and $O^{2-}$. The correct order of increasing ionic radii is:

Which of the following is the smallest in size?

The correct order of covalent radii of $Si$,$Ge$,and $Sn$ is:

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