(A) The stability of free radicals is determined by the number of alkyl groups attached to the carbon atom bearing the unpaired electron. Alkyl groups

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$3^\circ > 2^\circ > 1^\circ > \dot{C}H_3$

(A) The stability of free radicals is determined by the number of alkyl groups attached to the carbon atom bearing the unpaired electron. Alkyl groups provide stability through the inductive effect and hyperconjugation. As the number of alkyl groups increases,the stability of the free radical increases. Therefore,the order of stability is: $3^\circ$ (tertiary) > $2^\circ$ (secondary) > $1^\circ$ (primary) > $\dot{C}H_3$ (methyl radical).

Class 11 Chemistry 8-4.Organic Chemistry : Reaction mechanism Reactive Intermediates

Easy

What is the correct order of stability for free radicals?

A
$3^\circ > 2^\circ > 1^\circ > \dot{C}H_3$
B
$\dot{C}H_3 > 1^\circ > 2^\circ > 3^\circ$
C
$1^\circ > 2^\circ > 3^\circ > \dot{C}H_3$
D
$2^\circ > 1^\circ > 3^\circ > \dot{C}H_3$

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8-4.Organic Chemistry : Reaction mechanism

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Reactive Intermediates

Explain why $((CH_3)_3C)^+$ is more stable than $(CH_3CH_2)^+$ and $(CH_3)^+$ is the least stable carbocation.

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The lower stability of ethyl anion compared to methyl anion and the higher stability of ethyl radical compared to methyl radical,respectively,are due to

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Arrange the following carbanions in the decreasing order of stability:
$I. \ p-Br-C_6H_4-CH_2^-$
$II. \ C_6H_5-CH_2^-$
$III. \ p-CH_3O-C_6H_4-CH_2^-$
$IV. \ p-CHO-C_6H_4-CH_2^-$
$V. \ p-CH_3-C_6H_4-CH_2^-$
Choose the correct answer from the options given below:

DifficultJEE MAIN 2026

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Consider the following compound $(X)$:
$H-C \equiv C-CH_2-CH(CH_3)-CH_3$
The most stable and least stable carbon radicals,respectively,produced by homolytic cleavage of the corresponding $C-H$ bond are:

DifficultJEE MAIN 2025

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The stability of the following carbocations follows the order:

DifficultKVPY 2020

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What is the correct order of stability for free radicals?

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Explain why $((CH_3)_3C)^+$ is more stable than $(CH_3CH_2)^+$ and $(CH_3)^+$ is the least stable carbocation.

The lower stability of ethyl anion compared to methyl anion and the higher stability of ethyl radical compared to methyl radical,respectively,are due to

Arrange the following carbanions in the decreasing order of stability:$I. \ p-Br-C_6H_4-CH_2^-$$II. \ C_6H_5-CH_2^-$$III. \ p-CH_3O-C_6H_4-CH_2^-$$IV. \ p-CHO-C_6H_4-CH_2^-$$V. \ p-CH_3-C_6H_4-CH_2^-$Choose the correct answer from the options given below:

Consider the following compound $(X)$:$H-C \equiv C-CH_2-CH(CH_3)-CH_3$The most stable and least stable carbon radicals,respectively,produced by homolytic cleavage of the corresponding $C-H$ bond are:

The stability of the following carbocations follows the order:

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Arrange the following carbanions in the decreasing order of stability:
$I. \ p-Br-C_6H_4-CH_2^-$
$II. \ C_6H_5-CH_2^-$
$III. \ p-CH_3O-C_6H_4-CH_2^-$
$IV. \ p-CHO-C_6H_4-CH_2^-$
$V. \ p-CH_3-C_6H_4-CH_2^-$
Choose the correct answer from the options given below:

Consider the following compound $(X)$:
$H-C \equiv C-CH_2-CH(CH_3)-CH_3$
The most stable and least stable carbon radicals,respectively,produced by homolytic cleavage of the corresponding $C-H$ bond are: