What is the final product,C of the following | vedclass

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(A) Step $1$: The terminal alkyne $CH_3CH_2-C \equiv CH$ reacts with $NaNH_2$ to form an acetylide ion,which then undergoes an $S_N2$ reaction with $C

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$CH_3CH_2CH(Br)CH(Br)CH_2CH_3$

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(A) Step $1$: The terminal alkyne $CH_3CH_2-C \equiv CH$ reacts with $NaNH_2$ to form an acetylide ion,which then undergoes an $S_N2$ reaction with $CH_3CH_2Br$ to yield $A$ ($hex-3-yne$,$CH_3CH_2-C \equiv C-CH_2CH_3$).Step $2$: The reduction of $hex-3-yne$ $(A)$ with $Na$ in liquid $NH_3$ (Birch reduction) is a stereoselective reaction that produces $trans-hex-3-ene$ $(B)$.Step $3$: The addition of $Br_2$ in $CH_2Cl_2$ to $trans-hex-3-ene$ $(B)$ is an anti-addition reaction,which results in the formation of $3,4-dibromohexane$ $(C)$.Thus,the final product $C$ is $CH_3CH_2CH(Br)CH(Br)CH_2CH_3$.

What is the final product,$C$ of the following reaction sequence?
$CH_3CH_2-C \equiv CH$ $\xrightarrow[2. CH_3CH_2Br]{1. NaNH_2} A$ $\xrightarrow{Na, NH_3(liq.)} B$ $\xrightarrow{Br_2, CH_2Cl_2} C$

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What is the final product,$C$ of the following reaction sequence?$CH_3CH_2-C \equiv CH$ $\xrightarrow[2. CH_3CH_2Br]{1. NaNH_2} A$ $\xrightarrow{Na, NH_3(liq.)} B$ $\xrightarrow{Br_2, CH_2Cl_2} C$