What is the fraction of the mass of water due | vedclass

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(C) The molar mass of water $(H_2O)$ is $18 \, g/mol$.The mass of one molecule of water is $\frac{18}{N_A} \, g$,where $N_A$ is the Avogadro number.In

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$\frac{8}{18}$

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(C) The molar mass of water $(H_2O)$ is $18 \, g/mol$.The mass of one molecule of water is $\frac{18}{N_A} \, g$,where $N_A$ is the Avogadro number.In one molecule of water $(H_2O)$,there are $2$ hydrogen atoms and $1$ oxygen atom.Hydrogen $(^1H)$ has $0$ neutrons,while Oxygen $(^{16}O)$ has $8$ neutrons.Therefore,the total number of neutrons in one molecule of water is $8$.The mass of $8$ neutrons is $\frac{8}{N_A} \, g$.The fraction of the mass of water due to neutrons is calculated as: $\frac{	ext{Mass of neutrons}}{	ext{Total mass of water}} = \frac{8/N_A}{18/N_A} = \frac{8}{18}$.

What is the fraction of the mass of water due to neutrons?

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