What is the major product of the above Friedel-Crafts reaction?

The product $(X)$ of the reaction is:

Amongst the following, the total number of compounds soluble in aqueous $NaOH$ at room temperature is:
$(I)$ Benzaldehyde
$(II)$ $1$-Naphthol
$(III)$ $4$-(Dimethylamino)phenol
$(IV)$ $4$-Methylphenol
$(V)$ Benzoic acid
$(VI)$ $N,N$-Dimethylcyclohexanamine
$(VII)$ $1$-Naphthoic acid
$(VIII)$ $1,4$-Di-tert-butylbenzene
$(IX)$ $1$-Naphthylmethanol

In the following reaction,$X$ and $Y$ are respectively
$CH_3 COOH + NH_3$ $\longrightarrow X \stackrel{\Delta}{}$ ${\longrightarrow} Y + H_2 O$

The total number of carboxylic acid groups in the product $P$ is

The acidity of compounds $I-IV$ in water follows the order:
$I.$ ethanol
$II.$ acetic acid
$III.$ phenol
$IV.$ acetonitrile