In the following reaction,$X$ and $Y$ are respectively
$CH_3 COOH + NH_3$ $\longrightarrow X \stackrel{\Delta}{}$ ${\longrightarrow} Y + H_2 O$

An organic compound $(A)$ (molecular formula $C_{8}H_{16}O_{2}$) was hydrolysed with dilute sulphuric acid to give a carboxylic acid $(B)$ and an alcohol $(C)$. Oxidation of $(C)$ with chromic acid produced $(B)$. $(C)$ on dehydration gives but$-1-$ene. Write equations for the reactions involved.

Product $(G)$ is

$CH_3-C(=O)-OH$ $\xrightarrow{NaH^{14}CO_3} (A) (\text{gas})$ $\xrightarrow[(ii) H_3O^{+}]{(i) PhMgBr} (B)$
$CH_3-S(=O)_2-OH$ $\xrightarrow{NaH^{14}CO_3} (C) (\text{gas})$ $\xrightarrow[(ii) H_3O^{+}]{(i) PhMgBr} (D)$
Product $(B)$ and $(D)$ in the above reaction are:

Identify $Z$ in the following reaction sequence:
$CH_3COONH_4$ $\xrightarrow{\Delta} X$ $\xrightarrow{P_2O_5} Y$ $\xrightarrow{H_2O/H^+} Z$

The reagent$(s)$ required for the following conversion are: