$CH_3-C(=O)-OH$ $\xrightarrow{NaH^{14}CO_3} (A) (\text{gas})$ $\xrightarrow[(ii) H_3O^{+}]{(i) PhMgBr} (B)$
$CH_3-S(=O)_2-OH$ $\xrightarrow{NaH^{14}CO_3} (C) (\text{gas})$ $\xrightarrow[(ii) H_3O^{+}]{(i) PhMgBr} (D)$
Product $(B)$ and $(D)$ in the above reaction are:

  • A
    $Ph-COOH$ and $Ph-SO_3H$
  • B
    $Ph-^{14}COOH$ and $Ph-SO_3H$
  • C
    $Ph-^{14}COOH$ and $Ph-^{14}COOH$
  • D
    $Ph-COOH$ and $Ph-SO_3H$

Explore More

Similar Questions

The reaction of sodium acetate with acetyl chloride proceeds through which of the following mechanisms?

Difficult
View Solution

Match Column-$I$ with Column-$II$ based on the $pK_a$ values of the given carboxylic acids:
Column-$I$Column-$II$
$(A)$ $CF_3COOH$$(i)$ $3.41$
$(B)$ Benzoic acid$(ii)$ $4.76$
$(C)$ $CH_3COOH$$(iii)$ $0.23$
$(D)$ $4$-nitrobenzoic acid$(iv)$ $4.20$

The product of the following reaction is :

In the following reaction sequence,the compound $J$ is an intermediate.
$I$ $\xrightarrow{(CH_3CO)_2O / CH_3COONa} J$ $\xrightarrow[(ii) \text{ anhyd. } AlCl_3]{(i) H_2, Pd/C, (ii) SOCl_2} K$
$J \left( C_9H_8O_2 \right)$ gives effervescence on treatment with $NaHCO_3$ and positive Baeyer's test.
$1.$ The compound $K$ is
$2.$ The compound $I$ is
Give the answer for question $1$ and $2.$

Arrange the acidity of the given four compounds in decreasing order:
$(I)$ $CH_3COCH_2COCH_3$
$(II)$ $CH_3COCH_3$
$(III)$ $CH \equiv CH$
$(IV)$ $CH_3CHO$
Select the correct answer from the codes given below:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo