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(A) The reaction of allyl alcohol with excess $HBr$ proceeds in two steps: $1.$ Substitution of the hydroxyl group by bromine to form allyl bromide: $

Vedclass · Accepted Answer

$CH_3-CH(Br)-CH_2-Br$

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(A) The reaction of allyl alcohol with excess $HBr$ proceeds in two steps: $1.$ Substitution of the hydroxyl group by bromine to form allyl bromide: $CH_2=CH-CH_2-OH + HBr \rightarrow CH_2=CH-CH_2-Br + H_2O$ $2.$ Electrophilic addition of $HBr$ to the double bond of allyl bromide following Markovnikov's rule: $CH_2=CH-CH_2-Br + HBr \rightarrow CH_3-CH(Br)-CH_2-Br$ Therefore,the major product is $1,2$-dibromopropane.

What is the major product of the following reaction?
$H_2C = CH - CH_2 - OH \xrightarrow[excess]{HBr} \text{Product}$

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What is the major product of the following reaction? $H_2C = CH - CH_2 - OH \xrightarrow[excess]{HBr} \text{Product}$