What is the maximum value of x in the followi | vedclass

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(B) Periodic acid $(HIO_4)$ cleaves vicinal diols ($1$,$2$-diols) to form carbonyl compounds.It does not cleave ether linkages.In the given structure,

Vedclass · Accepted Answer

$2$

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(B) Periodic acid $(HIO_4)$ cleaves vicinal diols ($1$,$2$-diols) to form carbonyl compounds.It does not cleave ether linkages.In the given structure,there are three adjacent hydroxyl groups $(CHOH-CHOH-CHOH)$ and one terminal primary alcohol group $(CH_2OH)$ attached to a carbon that is also part of an ether linkage.Specifically,the sequence of diols available for cleavage are the three $CHOH$ groups.Periodic acid will cleave the bonds between these adjacent hydroxyl-bearing carbons.Since there are $3$ adjacent $CHOH$ groups,it requires $2$ moles of $HIO_4$ to cleave the two $C-C$ bonds between them.The ether linkage remains intact.Therefore,the value of $x$ is $2$.

What is the maximum value of $x$ in the following reaction?
$MeO-CH-(CHOH)_3-CH-CH_2OH$ (with a cyclic ether linkage between the first and fifth carbon) $+ xHIO_4 \rightarrow$ products

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What is the maximum value of $x$ in the following reaction?$MeO-CH-(CHOH)_3-CH-CH_2OH$ (with a cyclic ether linkage between the first and fifth carbon) $+ xHIO_4 \rightarrow$ products