What is the molar conductivity at infinite dilution of $CaCl_{2}$,if the molar conductivity of $Ca^{2+}$ ion and $Cl^{-}$ ion at infinite dilution is $119$ and $71 \ \Omega^{-1} \ cm^{2} \ mol^{-1}$ respectively?

The resistance of $0.05\, M$ solution of oxalic acid is $200\, \Omega$ and the cell constant is $2.0\, cm^{-1}$. The equivalent conductance in $S\, cm^2\, eq^{-1}$ will be:

When a certain conductivity cell was filled with $0.1 \ M \ KCl$,it had a resistance of $85 \ \Omega$ at $25 \ ^oC$. When the same cell was filled with an aqueous solution of $0.052 \ M$ unknown electrolyte,the resistance was $96 \ \Omega$. Calculate the molar conductivity of the unknown electrolyte at this concentration ............. $\Omega^{-1} \ cm^2 \ mol^{-1}$ (Given: Specific conductance of $0.1 \ M \ KCl = 1.29 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$)

Write the formula to calculate conductivity by using a conductivity cell.

The graphical variation of molar conductivity $(\Lambda_m)$ against the square root of molar concentration $(\sqrt{c})$ for a certain electrolyte '$X$' is linear with an intercept on the y-axis. Identify '$X$' from the following.

The specific conductivity of $N/10$ $KCl$ solution at $20 \, ^oC$ is $0.012 \, \Omega^{-1} \, cm^{-1}$ and the resistance of the solution in the cell at $20 \, ^oC$ is $56 \, \Omega$. The cell constant is ........... $cm^{-1}$.