What is the momentum of a photon having frequ | vedclass

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Question

(A) The momentum $p$ of a photon is given by the formula $p = \frac{E}{c}$,where $E = h
u$ is the energy of the photon.Substituting the values,we get

Vedclass · Accepted Answer

$3.3 	imes 10^{-29} \ kg \ m/s$

Vedclass · Answer

(A) The momentum $p$ of a photon is given by the formula $p = \frac{E}{c}$,where $E = h
u$ is the energy of the photon.Substituting the values,we get $p = \frac{h
u}{c}$.Given: $h = 6.6 	imes 10^{-34} \ J \ s$,$
u = 1.5 	imes 10^{13} \ Hz$,and $c = 3 	imes 10^8 \ m/s$.$p = \frac{6.6 	imes 10^{-34} 	imes 1.5 	imes 10^{13}}{3 	imes 10^8}$.$p = \frac{9.9 	imes 10^{-21}}{3 	imes 10^8} = 3.3 	imes 10^{-29} \ kg \ m/s$.

What is the momentum of a photon having frequency $1.5 \times 10^{13} \ Hz$?

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