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(A) The atomic number of $Co$ is $27$. The electronic configuration of $Co$ is $[Ar] 3d^7 4s^2$.In $[CoF_6]^{3-}$,the oxidation state of $Co$ is $x +

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$4$

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(A) The atomic number of $Co$ is $27$. The electronic configuration of $Co$ is $[Ar] 3d^7 4s^2$.In $[CoF_6]^{3-}$,the oxidation state of $Co$ is $x + 6(-1) = -3$,so $x = +3$.The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.$F^-$ is a weak field ligand,so it does not cause pairing of electrons in the $3d$ orbitals.Therefore,the $3d^6$ configuration remains as $t_{2g}^4 e_g^2$,which corresponds to $4$ unpaired electrons.

What is the number of unpaired electrons present in $[CoF_6]^{3-}$?

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