What is the phase difference between the flux | vedclass

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(D) The magnetic flux linked with a coil rotating in a uniform magnetic field is given by $\phi = BA \cos(\omega t)$,where $B$ is the magnetic field,$

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$\frac{\pi}{2}$

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(D) The magnetic flux linked with a coil rotating in a uniform magnetic field is given by $\phi = BA \cos(\omega t)$,where $B$ is the magnetic field,$A$ is the area of the coil,and $\omega$ is the angular velocity.According to Faraday's law of electromagnetic induction,the induced e.m.f. is given by $\epsilon = -\frac{d\phi}{dt}$.Substituting the expression for $\phi$,we get $\epsilon = -\frac{d}{dt} [BA \cos(\omega t)] = BA\omega \sin(\omega t)$.Using the trigonometric identity $\sin(	heta) = \cos(	heta - \frac{\pi}{2})$,we can write $\epsilon = BA\omega \cos(\omega t - \frac{\pi}{2})$.Comparing the phase of the flux $(\omega t)$ and the phase of the induced e.m.f. $(\omega t - \frac{\pi}{2})$,the phase difference is $\frac{\pi}{2}$.

What is the phase difference between the flux linked with a coil rotating in a uniform magnetic field and the induced e.m.f. produced in it?

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