What is the position and nature of the image formed by the lens combination shown in the figure? ($f_1, f_2$ are focal lengths)

  • A
    $70 \, cm$ from point $B$ at left; virtual
  • B
    $40 \, cm$ from point $B$ at right; real
  • C
    $\frac{20}{3} \, cm$ from point $B$ at right; real
  • D
    $70 \, cm$ from point $B$ at right; real

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$A$ bi-convex lens is formed with two thin plano-convex lenses as shown in the figure. The refractive index $n$ of the first lens is $1.5$ and that of the second lens is $1.2$. Both the curved surfaces are of the same radius of curvature $R = 14 \, cm$. For this bi-convex lens,for an object distance of $40 \, cm$,the image distance will be.......$cm$

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Find the distance of the final image from the object $O$,formed by the combination of lenses shown in the figure (in $cm$):

The combination of a convex lens $(f = 18 \ cm)$ and a thin concave lens $(f = 9 \ cm)$ is:

Two lenses have focal lengths of $+10 \ cm$ and $-15 \ cm$. When they are placed in contact,the combination acts as a convex lens. If the chromatic aberration is zero,what is the ratio of their dispersive powers?

$A$ plano-convex lens fits exactly into a plano-concave lens. Their plane surfaces are parallel to each other. If the lenses are made of different materials with refractive indices $\mu_1$ and $\mu_2$ and $R$ is the radius of curvature of the curved surface of the lenses,then the focal length of the combination is:

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