What is the quantity of sugar charcoal remain | vedclass

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(A) The dehydration reaction of sugar $(C_{12}H_{22}O_{11})$ by conc. $H_2SO_4$ is given by: $C_{12}H_{22}O_{11} \rightarrow 12C + 11H_2O$ First,calcu

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$7.2$

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(A) The dehydration reaction of sugar $(C_{12}H_{22}O_{11})$ by conc. $H_2SO_4$ is given by: $C_{12}H_{22}O_{11} ightarrow 12C + 11H_2O$ First,calculate the number of moles of sugar: Molar mass of $C_{12}H_{22}O_{11} = (12 	imes 12) + (22 	imes 1) + (11 	imes 16) = 342 \ g/mol$. Moles of sugar $= \frac{17.1 \ g}{342 \ g/mol} = 0.05 \ mol$. According to the stoichiometry,$1 \ mol$ of sugar produces $12 \ mol$ of carbon (charcoal). Therefore,$0.05 \ mol$ of sugar produces $0.05 	imes 12 = 0.6 \ mol$ of carbon. Mass of charcoal $= 0.6 \ mol 	imes 12 \ g/mol = 7.2 \ g$.

What is the quantity of sugar charcoal remaining behind after charring $17.1 \ g$ of sugar using conc. $H_2SO_4$ under ideal conditions (in $g$)?

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