What is the solubility of a gas in water at $25^{\circ} C$ if the partial pressure is $0.18 \ atm$? $(K_{H} = 0.16 \ mol \ dm^{-3} \ atm^{-1})$
- A$0.029 \ mol \ dm^{-3}$
- B$0.022 \ mol \ dm^{-3}$
- C$0.032 \ mol \ dm^{-3}$
- D$0.038 \ mol \ dm^{-3}$
Explore More
Similar Questions
The variation of solubility with temperature $T$ for a gas in a liquid is shown by the following graphs. The correct representation is:
Explain the equilibrium in soda water and explain it using Henry's law.
Medium
View SolutionThe $K_{H}$ values for some gases at the same temperature '$T$' are given below:
Gas
$K_{H} / \text{kbar}$
$Ar$
$40.3$
$CO_{2}$
$1.67$
$HCHO$
$1.83 \times 10^{-5}$
$CH_{4}$
$0.413$
where $K_{H}$ is Henry's Law constant in water. The order of their solubility in water is:
| Gas | $K_{H} / \text{kbar}$ |
|---|---|
| $Ar$ | $40.3$ |
| $CO_{2}$ | $1.67$ |
| $HCHO$ | $1.83 \times 10^{-5}$ |
| $CH_{4}$ | $0.413$ |
where $K_{H}$ is Henry's Law constant in water. The order of their solubility in water is:
If the solubility of $NaCl$ at $20\,^{\circ}C$ is $35\,g$ per $100\,g$ of water,then on adding $50\,g$ of $NaCl$ to the same amount of water at the same temperature,the amount of salt that remains undissolved is .......... $g$.
Easy
View SolutionCalculate $K_H$ when $2 \ mmol$ of $O_2$ dissolve in $540 \ mL$ of water at $27 \ ^oC$ temperature. Given $P_{O_2} = 2 \times 10^{-8} \ bar$.
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo