What is the time required for completion of $90 \%$ of a first order reaction?

  • A
    $\frac{2.303}{k}$
  • B
    $\frac{2.303}{k} \log 10$
  • C
    $\frac{0.693}{k}$
  • D
    $\frac{2 \times 0.693}{k}$

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$A$ flask is filled with equal moles of $A$ and $B$. The half-lives of $A$ and $B$ are $100 \, s$ and $50 \, s$ respectively and are independent of the initial concentration. The time required for the concentration of $A$ to be four times that of $B$ is $.... \, s.$
(Given : $\ln 2 = 0.693$ )

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