What is the value of n in the anionic species | vedclass

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(D) The $EAN$ (Effective Atomic Number) rule states that the total number of electrons around the central metal atom in a complex should equal the ato

Vedclass · Accepted Answer

$-1$

Vedclass · Answer

(D) The $EAN$ (Effective Atomic Number) rule states that the total number of electrons around the central metal atom in a complex should equal the atomic number of the next noble gas.For Vanadium $(V)$,the atomic number $(Z)$ is $23$.The next noble gas is Krypton $(Kr)$ with an atomic number of $36$.The complex is $[V(CO)_6]^{n-}$.The number of electrons contributed by $6$ $CO$ ligands is $6 	imes 2 = 12$ electrons.The number of electrons in the metal ion $V^{n+}$ is $23 - n$.According to the $EAN$ rule: $(23 - n) + 12 = 36$.$35 - n = 36$.$n = 35 - 36 = -1$.Therefore,the value of $n$ is $-1$.

What is the value of $n$ in the anionic species $[V(CO)_6]^{n-}$ if it follows the Sidgwick $EAN$ rule and has an octahedral shape?

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