What least number must be added to 7231 so th | vedclass

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(C) To be divisible by both $5$ and $9,$ the number must be divisible by their least common multiple $(LCM)$.Since $5$ and $9$ are coprime,their $LCM

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$14$

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(C) To be divisible by both $5$ and $9,$ the number must be divisible by their least common multiple $(LCM)$.Since $5$ and $9$ are coprime,their $LCM = 5 	imes 9 = 45.$Now,divide $7231$ by $45$ to find the remainder:$7231 \div 45 = 160$ with a remainder of $31.$To make the number exactly divisible by $45,$ we need to add the difference between the divisor and the remainder to the original number.Required number $= 45 - 31 = 14.$

What least number must be added to $7231$ so that the resulting number is exactly divisible by $5$ and $9$ together?

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