What must be the molarity of $BaCl_2$ solution to have molar conductivity $240 \text{ } \Omega^{-1} \text{cm}^2 \text{mol}^{-1}$ and conductivity $0.012 \text{ } \Omega^{-1} \text{cm}^{-1}$ at $25^{\circ} \text{C}$ (in $\text{ M}$)?

$\wedge_{AgCl}^{\infty}$ can be obtained by:

Resistance of $0.05 \ M$ electrolytic solution at $298 \ K$ temperature is $30.0 \ \Omega$. The cross-sectional area of the conductivity cell having $Pt$ electrodes is $3.8 \ cm^{2}$ and the distance between the two electrodes is $1.5 \ cm$. What is the molar conductivity of the electrolytic solution?

When is the conductance $G$ equal to the conductivity $k$?

The molar conductivity of a $0.5 \ mol/dm^3$ solution of $AgNO_3$ with electrolytic conductivity of $5.76 \times 10^{-3} \ S \ cm^{-1}$ at $298 \ K$ is ......... $S \ cm^2/mol$.

Calculate the molar conductivity of $0.2 \text{ M}$ $KCl$ solution at $298 \text{ K}$ if the conductivity $(k)$ is $0.0248 \text{ } \Omega^{-1} \text{cm}^{-1}$.