What type of hybridization is present in Ni o | vedclass

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(B) In $[NiCl_4]^{2-}$,$Ni$ is in $+2$ oxidation state: $Ni^{2+} \rightarrow [Ar] 3d^8$.Since $Cl^-$ is a weak field ligand,it does not cause pairing

Vedclass · Accepted Answer

$sp^3$ and $dsp^2$

Vedclass · Answer

(B) In $[NiCl_4]^{2-}$,$Ni$ is in $+2$ oxidation state: $Ni^{2+} \rightarrow [Ar] 3d^8$.Since $Cl^-$ is a weak field ligand,it does not cause pairing of $3d$ electrons.Thus,the hybridization involved is $sp^3$ using $4s$ and $4p$ orbitals.In $[Ni(CN)_4]^{2-}$,$Ni$ is in $+2$ oxidation state: $Ni^{2+} \rightarrow [Ar] 3d^8$.$CN^-$ is a strong field ligand,which causes pairing of $3d$ electrons.This leaves one $3d$ orbital vacant,resulting in $dsp^2$ hybridization using one $3d$,one $4s$,and two $4p$ orbitals.

List - $I$ (Complex)	List – $II$ (Geometry)
$(a)$ $[Co(NH_3)_6]^{3+}$	$(i)$ Trigonal bipyramidal
$(b)$ $[NiCl_4]^{2-}$	(ii) Octahedral
$(c)$ $[Ni(CN)_4]^{2-}$	(iii) Tetrahedral
$(d)$ $[Fe(CO)_5]$	(iv) Square planar

What type of hybridization is present in $Ni$ of $[Ni(Cl)_4]^{2-}$ and $[Ni(CN)_4]^{2-}$ respectively?

Similar Questions

The shape of the $[Fe(CN)_6]^{4-}$ ion is:

Consider the reaction $K_2[Ni(CN)_4] + 4K + 4NH_3 \to A$ (complex $A$).
Complex $A$ gives five ions in aqueous solution. Choose the $CORRECT$ statements.

Assertion $:$ Complex ion $[Co(NH_3)_6]^{2+}$ is readily oxidized to $[Co(NH_3)_6]^{3+}$.
Reason $:$ Unpaired electron in complex ion $[Co(NH_3)_6]^{2+}$ is present in $4p$ orbital.

Which of the following statements is incorrect regarding $[Ni(dmg)_2]$?

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