What will be the mass of a particle if uncert | vedclass

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(A) According to Heisenberg's uncertainty principle: $\Delta x \cdot m \Delta v \geq \frac{h}{4 \pi}$.Rearranging for mass $(m)$: $m = \frac{h}{4 \pi

Vedclass · Accepted Answer

$0.01$

Vedclass · Answer

(A) According to Heisenberg's uncertainty principle: $\Delta x \cdot m \Delta v \geq \frac{h}{4 \pi}$.Rearranging for mass $(m)$: $m = \frac{h}{4 \pi \Delta x \Delta v}$.Given: $h = 6.626 	imes 10^{-34} \ J \ s$,$\Delta x = 10^{-8} \ m$,$\Delta v = 5.26 	imes 10^{-25} \ m \ s^{-1}$.Substituting the values: $m = \frac{6.626 	imes 10^{-34}}{4 	imes 3.14159 	imes 10^{-8} 	imes 5.26 	imes 10^{-25}}$.$m = \frac{6.626 	imes 10^{-34}}{6.608 	imes 10^{-32}} \approx 0.01 \ kg$.

What will be the mass of a particle if uncertainty in its position is $10^{-8} \ m$ and uncertainty in velocity is $5.26 \times 10^{-25} \ m \ s^{-1}$? ............... $kg$

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