When 0.1 mol of CoCl_3(NH_3)_5 is treated wi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of the coordination compound with $AgNO_3$ precipitates only the chloride ions $(Cl^-)$ present outside the coordination sphere.Given

Vedclass · Accepted Answer

$[CoCl(NH_3)_5]Cl_2$

Vedclass · Answer

(B) The reaction of the coordination compound with $AgNO_3$ precipitates only the chloride ions $(Cl^-)$ present outside the coordination sphere.Given that $0.1 \ mol$ of the complex yields $0.2 \ mol$ of $AgCl$,the ratio of $AgCl$ to the complex is $2:1$.This indicates that there are $2$ ionizable $Cl^-$ ions outside the coordination sphere.Therefore,the formula is $[Co(NH_3)_5Cl]Cl_2$.

When $0.1 \ mol$ of $CoCl_3(NH_3)_5$ is treated with an excess of $AgNO_3$,$0.2 \ mol$ of $AgCl$ are obtained. The formula of the compound is:

Similar Questions

Which of the following is a basic ligand?

How many ions are produced from $[Co(NH_3)_6]Cl_3$ in solution?

The coordination number of a metal in coordination compounds is

What is the coordination number of $Fe$ in $[Fe(CN)_6]^{3-}$?

Identify the homoleptic complex from the following:

Vedclass Test Series

Exam Paper Generator

Online Exam Module