When 100 , V DC is applied across a coil,a cu | vedclass

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(B) When $DC$ is supplied,the coil acts as a pure resistor because the frequency is zero. Therefore,the resistance $R$ is given by $R = \frac{V}{I_{DC

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$200$

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(B) When $DC$ is supplied,the coil acts as a pure resistor because the frequency is zero. Therefore,the resistance $R$ is given by $R = \frac{V}{I_{DC}} = \frac{100 \, V}{1 \, A} = 100 \, \Omega$.When $AC$ is supplied,the coil offers both resistance and inductive reactance. The total opposition to the current is called impedance $(Z)$.Using Ohm's law for $AC$ circuits,$Z = \frac{V}{I_{AC}} = \frac{100 \, V}{0.5 \, A} = 200 \, \Omega$.Thus,the impedance of the coil is $200 \, \Omega$.

When $100 \, V$ $DC$ is applied across a coil,a current of $1 \, A$ flows through it. When $100 \, V$ $AC$ at $50 \, Hz$ is applied to the same coil,only $0.5 \, A$ current flows. The impedance of the coil is ....... $\Omega$.

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