When a sample of gas is compressed at constan | vedclass

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(A) Given,$P_1 = 15 \, atm$,$P_2 = 60 \, atm$.$V_1 = 76 \, cm^3$,$V_2 = 20.5 \, cm^3$.If the gas is an ideal gas,then according to Boyle's law,it must

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$1, 2, 	ext{ and } 3$

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(A) Given,$P_1 = 15 \, atm$,$P_2 = 60 \, atm$.$V_1 = 76 \, cm^3$,$V_2 = 20.5 \, cm^3$.If the gas is an ideal gas,then according to Boyle's law,it must follow the equation $P_1V_1 = P_2V_2$.$P_1 	imes V_1 = 15 	imes 76 = 1140$.$P_2 	imes V_2 = 60 	imes 20.5 = 1230$.Since $P_1V_1 
eq P_2V_2$,the gas behaves non-ideally.Additionally,processes like dimerization or adsorption on vessel walls would also lead to a deviation from the expected ideal volume change,making all three statements possible explanations for the observed behavior.

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