When a solute is present in trace quantities,the following expression is used:

What is the molarity of a $1 \ L$ solution of $93\% \ (w/v)$ $H_2SO_4$ (in $M$)? The density of the solution is $1.84 \ g/mL$.

Calculate the molarity of a solution prepared by dissolving $7.1 \ g$ of sodium sulfate $(Na_2SO_4)$ in water to make $100 \ mL$ of solution. (in $M$)

Dissolving $120 \ g$ of urea (mol. wt. $60$) in $1000 \ g$ of water gave a solution of density $1.15 \ g / mL$. The molarity of the solution is (in $M$)

$25 \ g$ of a solute of molar mass $250 \ g \ mol^{-1}$ is dissolved in $100 \ mL$ of water to obtain a solution whose density is $1.25 \ g \ mL^{-1}$. The molarity and molality of the solution are respectively

What will be the molarity of a solution containing $5 \ g$ of sodium hydroxide in $250 \ mL$ solution?