When a stone of mass m falls through a vertic | vedclass

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(A) The gravitational potential energy $(PE)$ of an object of mass $m$ at a height $h$ above the ground is given by the formula $PE = mgh$.When the st

Vedclass · Accepted Answer

$m g d$

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(A) The gravitational potential energy $(PE)$ of an object of mass $m$ at a height $h$ above the ground is given by the formula $PE = mgh$.When the stone falls through a vertical height $d$,its initial height is $h_i$ and its final height is $h_f = h_i - d$.The change in gravitational potential energy is $\Delta PE = PE_i - PE_f$.$\Delta PE = mgh_i - mg(h_i - d)$.$\Delta PE = mgh_i - mgh_i + mgd$.$\Delta PE = mgd$.Therefore,the decrease in gravitational potential energy is $mgd$.

When a stone of mass $m$ falls through a vertical height $d$,the decrease in the gravitational potential energy is:

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