When acetone is added to chloroform,then a hy | vedclass

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Question

(B) When acetone $(CH_3COCH_3)$ is mixed with chloroform $(CHCl_3)$,a strong intermolecular hydrogen bond is formed between the oxygen atom of acetone

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Negative deviation from Raoult's law

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(B) When acetone $(CH_3COCH_3)$ is mixed with chloroform $(CHCl_3)$,a strong intermolecular hydrogen bond is formed between the oxygen atom of acetone and the hydrogen atom of chloroform.This interaction makes the attraction between the molecules of $A$ and $B$ stronger than the individual $A-A$ or $B-B$ interactions.As a result,the escaping tendency of both components decreases,leading to a lower vapour pressure than expected for an ideal solution.Therefore,this mixture shows a negative deviation from Raoult's law.

When acetone is added to chloroform,then a hydrogen bond is formed between them. These liquids show:

Similar Questions

$A$ solution of two miscible liquids showing negative deviation from Raoult's law will have :

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