(B) The $K$ shell is the first shell $(n=1)$ and the $L$ shell is the second shell $(n=2)$.Since the $K$ shell is closer to the nucleus,it has lower e

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(B) The $K$ shell is the first shell $(n=1)$ and the $L$ shell is the second shell $(n=2)$.Since the $K$ shell is closer to the nucleus,it has lower energy than the $L$ shell.When an electron transitions from a higher energy level ($L$ shell) to a lower energy level ($K$ shell),the difference in energy is emitted as a photon.Therefore,energy is released.

Class 11 Chemistry Structure of Atom Atomic models and Planck's quantum theory

Easy

When an electron jumps from $L$ to $K$ shell,what happens to the energy?

A
Energy is absorbed
B
Energy is released
C
Energy is sometimes absorbed and sometimes released
D
Energy is neither absorbed nor released

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Class 11 Questions

Class 11

Chemistry Questions

Chapter

Structure of Atom

Subtopic

Atomic models and Planck's quantum theory

The ratio of velocity of electron in the second orbit of $He^{+}$ to the third orbit of $B^{4+}$ is $:-$

Medium

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Energy and radius of the first Bohr orbit of $He^{+}$ and $Li^{2+}$ are: $[$Given $R_{H} = 2.18 \times 10^{-18} \ J, a_{0} = 52.9 \ pm$ $]$

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Supposing the electron is present in the $4^{th}$ energy level of $H$ atom. When the electron returns to the ground state,the possible transitions would be:

Easy

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Calculate the energy of $1 \ mol$ of photons having a frequency of $4.0 \times 10^{14} \ Hz$.

Easy

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Bohr’s model of atom explains :

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When an electron jumps from $L$ to $K$ shell,what happens to the energy?

Similar Questions

The ratio of velocity of electron in the second orbit of $He^{+}$ to the third orbit of $B^{4+}$ is $:-$

Energy and radius of the first Bohr orbit of $He^{+}$ and $Li^{2+}$ are: $[$Given $R_{H} = 2.18 \times 10^{-18} \ J, a_{0} = 52.9 \ pm$ $]$

Supposing the electron is present in the $4^{th}$ energy level of $H$ atom. When the electron returns to the ground state,the possible transitions would be:

Calculate the energy of $1 \ mol$ of photons having a frequency of $4.0 \times 10^{14} \ Hz$.

Bohr’s model of atom explains :

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