When the momentum of a body increases by 100% | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The kinetic energy $(KE)$ of a body is related to its momentum $(p)$ by the formula: $KE = \frac{p^2}{2m}$,where $m$ is the mass of the body.Let t

Vedclass · Accepted Answer

$300$

Vedclass · Answer

(C) The kinetic energy $(KE)$ of a body is related to its momentum $(p)$ by the formula: $KE = \frac{p^2}{2m}$,where $m$ is the mass of the body.Let the initial momentum be $p_1 = p$. Then the initial kinetic energy is $KE_1 = \frac{p^2}{2m}$.When the momentum increases by $100\%$,the new momentum $p_2$ becomes:$p_2 = p + 100\% 	ext{ of } p = p + p = 2p$.The new kinetic energy $KE_2$ is:$KE_2 = \frac{(2p)^2}{2m} = \frac{4p^2}{2m} = 4 	imes KE_1$.The percentage increase in kinetic energy is given by:$	ext{Percentage Increase} = \frac{KE_2 - KE_1}{KE_1} 	imes 100\%$$= \frac{4 KE_1 - KE_1}{KE_1} 	imes 100\%$$= \frac{3 KE_1}{KE_1} 	imes 100\% = 300\%$.

When the momentum of a body increases by $100\%$,its $KE$ increases by .............. $\%$

Similar Questions

$A$ man increases his speed by $2 \ m/s$, and as a result, his kinetic energy doubles. What was his initial speed?

$A$ $4 \,kg$ mass and a $1 \,kg$ mass are moving with equal kinetic energies. The ratio of the magnitude of their linear momenta is

The masses of two substances are $4 \text{ g}$ and $9 \text{ g}$ respectively. If their kinetic energies are the same,then the ratio of their momenta will be

The kinetic energy of a body of mass $4 \,kg$ and momentum $6 \,Ns$ will be (in $\,J$)

Express momentum in terms of mass and kinetic energy.

Vedclass Test Series

Exam Paper Generator

Online Exam Module