When will a body of mass $20 \ kg$ moving at $15 \ m s^{-1}$,subjected to a retarding force of $100 \ N$,come to rest (in $s$)?

$A$ force $\vec{F}=(40 \hat{i}+10 \hat{j}) \, N$ acts on a body of mass $5 \, kg$. If the body starts from rest,its position vector $\vec{r}$ at time $t=10 \, s$ will be -

$A$ body of mass $2 \ kg$ moving with velocity of $\overrightarrow{v}_{in} = 3 \hat{i} + 4 \hat{j} \ ms^{-1}$ enters into a constant force field of $6 \ N$ directed along the positive $z$-axis. If the body remains in the field for a period of $\frac{5}{3} \ s$, then the velocity of the body when it emerges from the force field is:

$A$ block of mass $1 \ kg$ starts from rest at $x=0$ and moves along the $X$-axis under the action of a force $F=kt$, where $t$ is time and $k=1 \ Ns^{-1}$. The distance the block will travel in $6 \ seconds$ is: (in $m$)

$A$ particle of mass $m$ is at rest at the origin at time $t = 0$. It is subjected to a force $F(t) = F_0e^{-bt}$ in the $x$-direction. Its speed $v(t)$ is depicted by which of the following curves?

From the following graph,find the magnitude of the negative force in $N$.