Where Nu = Nucleophile. Find out the correct | vedclass

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(C) In reaction $(I)$,the substrate has an electron-donating group $(-OMe)$ at the para position,which stabilizes the carbocation intermediate. This f

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Reaction $(I)$ is of $1^{st}$ order and reaction $(II)$ is of $2^{nd}$ order

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(C) In reaction $(I)$,the substrate has an electron-donating group $(-OMe)$ at the para position,which stabilizes the carbocation intermediate. This facilitates the $S_N1$ mechanism,which is a $1^{st}$ order reaction.In reaction $(II)$,the substrate has an electron-withdrawing group $(-NO_2)$ at the para position,which destabilizes the carbocation intermediate,making the $S_N1$ pathway unfavorable. Instead,it proceeds via the $S_N2$ mechanism,which is a $2^{nd}$ order reaction.Therefore,reaction $(I)$ is of $1^{st}$ order and reaction $(II)$ is of $2^{nd}$ order.

Where $Nu =$ Nucleophile. Find out the correct statement from the options given below for the above $2$ reactions.

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