Which among the following compounds undergoes | vedclass

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(D) The rate of $SN^2$ reaction depends on two main factors: $1$. Steric hindrance: The rate of $SN^2$ reaction is inversely proportional to the steri

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$CH_3CH_2CH_2CH_2I$

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(D) The rate of $SN^2$ reaction depends on two main factors: $1$. Steric hindrance: The rate of $SN^2$ reaction is inversely proportional to the steric hindrance around the electrophilic carbon. The order of reactivity is $CH_3-X > 1^{\circ} > 2^{\circ} > 3^{\circ}$ alkyl halides. $2$. Leaving group ability: If the alkyl group is the same,the rate of $SN^2$ reaction is directly proportional to the leaving group ability. The order of leaving group ability is $I^- > Br^- > Cl^- > F^-$. Comparing the given options: - Options $A$,$B$,and $D$ are primary $(1^{\circ})$ alkyl halides. - Option $C$ is a secondary $(2^{\circ})$ alkyl halide,which is slower than primary halides due to higher steric hindrance. - Among the primary halides ($A$,$B$,and $D$),the leaving group ability determines the rate. Since $I^-$ is the best leaving group among $Cl^-$,$Br^-$,and $I^-$,$CH_3CH_2CH_2CH_2I$ undergoes $SN^2$ reaction most rapidly.

Which among the following compounds undergoes $SN^2$ reaction most rapidly?

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